(n^2-3n)-(x^2-3x)=32

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Solution for (n^2-3n)-(x^2-3x)=32 equation: 


Simplifying
(n2 + -3n) + -1(x2 + -3x) = 32

Reorder the terms:
(-3n + n2) + -1(x2 + -3x) = 32

Remove parenthesis around (-3n + n2)
-3n + n2 + -1(x2 + -3x) = 32

Reorder the terms:
-3n + n2 + -1(-3x + x2) = 32
-3n + n2 + (-3x * -1 + x2 * -1) = 32
-3n + n2 + (3x + -1x2) = 32

Solving
-3n + n2 + 3x + -1x2 = 32

Solving for variable 'n'.

Reorder the terms:
-32 + -3n + n2 + 3x + -1x2 = 32 + -32

Combine like terms: 32 + -32 = 0
-32 + -3n + n2 + 3x + -1x2 = 0

The solution to this equation could not be determined.

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